How much heat energy will be required to increase the temperature of the vessel in part (a) from $25^{\circ} C$ to $35^{\circ} C$ ?

915 J

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41230 J

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315 J

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615 J

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Solution

The correct option is D $615 J$
Here, $Δ θ = 35 - 25 = 10^{o} C$
so, heat required is $61.5 \times 10 = 615 J$

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Q. A copper vessel has mass

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and the specific heat capacity of copper is

410 J k g^{- 1} K^{- 1}

. How much heat energy will be required to increase the temperature of the vessel in from

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(a) Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J $k g^{- 1} K^{- 1}$ .

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Q. How much energy will it take for 0.5 kg water to rise from a temperature of 25℃ to 35℃?

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How much heat energy will be required to increase the temperature of the vessel in part (a) from 25∘C to 35∘C ?

The correct option is D 615JHere, Δθ=35−25=10oCso, heat required is 61.5×10=615 J

How much heat energy will be required to increase the temperature of the vessel in part (a) from $25^{\circ} C$ to $35^{\circ} C$ ?

The correct option is D $615 J$
Here, $Δ θ = 35 - 25 = 10^{o} C$
so, heat required is $61.5 \times 10 = 615 J$