How much hydrostatic pressure is exerted by water at the bottom of a beaker in Pascal? Take the depth of water as $45 c m$ . (density of water $10^{3} k g$ $m^{- 3}$ )

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Solution

Hydrostatic pressure = $ϱ g h P_{a}$
= $10^{3} k g / m^{3} \times 9.8 \frac{m}{5^{2}} \times 0.45 m$
Hydrostatic Pressure = 4410 $P_{a}$

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How much hydrostatic pressure is exerted by water at the bottom of a beaker in Pascal? Take the depth of water as 45cm. (density of water 103kg m−3)

Hydrostatic pressure = ϱghPa = 103kg/m3×9.8m52×0.45mHydrostatic Pressure = 4410 Pa

How much hydrostatic pressure is exerted by water at the bottom of a beaker in Pascal? Take the depth of water as $45 c m$ . (density of water $10^{3} k g$ $m^{- 3}$ )

Hydrostatic pressure = $ϱ g h P_{a}$
= $10^{3} k g / m^{3} \times 9.8 \frac{m}{5^{2}} \times 0.45 m$
Hydrostatic Pressure = 4410 $P_{a}$