Question

Water and oil are taken in two separate beakers, the density of water is 1000 kg/m${}^3$ and the density of oil is 1500 kg/m${}^3$. At what depth, the pressure in oil beaker will be the same as the pressure at 150 cm depth, in the water beaker ?

• A. 150
• B. 50
• C. 75
• D. 100

Answer 1

The correct option is D

100

P= h x ρ x g.

let the depth at which the pressure in oil is same as in water at 150 cm be Y.

The pressure in water at 150 cm = The pressure in oil at Y cm.

150 x 1000 x g = Y x 1500 x g

150 x 1000 = Y x 1500

$Y=\frac{150\times 1000}{1500}$

Y = 100 cm.