Two beakers are filled to the same depth, one with water and one with oil. The density of water is $1000$ kg $/ m^{3}$ and the density of oil is $920$ kg $/ m^{3}$ . In which position is the pressure the greatest?

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Solution

Let $m_{1}$ be the mass of water and $m_{2}$ be the mass of oil since volume of both liquids are same denoting it as V
density of water= $\frac{m_{1}}{V} = 1000 k g / m^{3}$
density of oil= $\frac{m_{2}}{V} = 920 k g / m^{3}$
so $∴ V = \frac{m_{1}}{1000} = \frac{m_{2}}{920}$
$∴ m_{2} = 0.92 \times m_{1}$
$∴ m_{1} > m_{2}$
this shows mass of water is greater than oil hence water will exert greater pressure on position $B$ .

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Two beakers are filled to the same depth, one with water and one with oil. The density of water is 1000 kg/m3 and the density of oil is 920 kg/m3. In which position is the pressure the greatest?

Two beakers are filled to the same depth, one with water and one with oil. The density of water is $1000$ kg $/ m^{3}$ and the density of oil is $920$ kg $/ m^{3}$ . In which position is the pressure the greatest?