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Question

How much is the work done in pulling up a block of wood weighing $2 k N$ for a length of $10 m$ on a smooth plane inclined at an angle of $30^{o}$ with the horizontal?

1.732 k J

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17.32 k J

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10 k J

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100 k J

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Solution

The correct option is C $10 k J$
Work done= change in potential energy
$W = m g h = 2000 \times 10 \times s i n θ = 10 k J$

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Similar questions

Q. The work done in pulling up a block of wood weighing

2 k N

for a length of

10 m

on a smooth plane inclined at an angle of

15^{o}

with the horizontal is:

The work done in pulling up a block of wood weighing 2kN for a length of 10 m on a smooth plane inclined at an angle of $15^{\circ}$ with the horizontal is $(s i n 15^{\circ} = 0.259)$

Q. The work done in pulling up a block of wood weighing

2 k N

through a distance length of

10 m

on a smooth plane inclined at an angle of

15^{o}

with the horizontal is

(

sin 15^{o} = 0.2588

)

Q. The work done in slowly pulling up a block of wood weighing 2kN for a length of 10m on a smooth plane inclined at an angle of

15^{\circ}

with the horizontal by a force parallel to the incline is :?

(s i n 15^{\circ} = 0.26, c o s 15^{\circ} = 0.96)

Q. The work done in slowly pulling up a block of wood weighing 2 kN for a length of 10m on a smooth plane inclined at an angle of

15^{\circ}

with the horizontal by a force parallel to the incline is:

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How much is the work done in pulling up a block of wood weighing 2kN for a length of 10m on a smooth plane inclined at an angle of 30o with the horizontal?

The correct option is C 10kJWork done= change in potential energyW=mgh=2000×10×sinθ=10 kJ

How much is the work done in pulling up a block of wood weighing $2 k N$ for a length of $10 m$ on a smooth plane inclined at an angle of $30^{o}$ with the horizontal?

The correct option is C $10 k J$
Work done= change in potential energy
$W = m g h = 2000 \times 10 \times s i n θ = 10 k J$