The work done in slowly pulling up a block of wood weighing 2 kN for a length of 10m on a smooth plane inclined at an angle of $15^{\circ}$ with the horizontal by a force parallel to the incline is:

4.36 k J

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5.17 k J

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8.91 k J

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9.82 k J

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Solution

The correct option is D $5.17 k J$
weight of wood $m g = 2 k N$
work done $= m g h$ ; $h = 10 s i n 15^{0} = 2.588 m$
$= 2 \times 2.588 = 5.17 J$

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Similar questions

Q. The work done in slowly pulling up a block of wood weighing 2kN for a length of 10m on a smooth plane inclined at an angle of

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The work done in slowly pulling up a block of wood weighing 2 kN for a length of 10m on a smooth plane inclined at an angle of 15∘ with the horizontal by a force parallel to the incline is:

The correct option is D 5.17kJweight of wood mg=2kNwork done =mgh; h=10sin150=2.588m=2×2.588=5.17J

The work done in slowly pulling up a block of wood weighing 2 kN for a length of 10m on a smooth plane inclined at an angle of $15^{\circ}$ with the horizontal by a force parallel to the incline is:

The correct option is D $5.17 k J$
weight of wood $m g = 2 k N$
work done $= m g h$ ; $h = 10 s i n 15^{0} = 2.588 m$
$= 2 \times 2.588 = 5.17 J$