How much is the work done in pulling up a block of wood weighing $2 K N$ for a length of $10 m$ on a smooth plane inclined at an angle of $30^{o}$ with the horizontal ? (in kJ)

1.732

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17.32

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10

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100

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Solution

The correct option is C $10$
Work done $W = F . s cos θ$
Here $θ =$ angle b/w force and displacement
As force is acting only in the vertically upward direction
$\Rightarrow θ = 90^{o} - 30^{o} = 60^{o}$
$\Rightarrow W = 2 \times 10 \times cos 60 = 10 k J$

Hence correct answer is option $C$

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How much is the work done in pulling up a block of wood weighing 2KN for a length of 10m on a smooth plane inclined at an angle of 30o with the horizontal ? (in kJ)

The correct option is C 10Work done W=F.scosθHere θ=angle b/w force and displacementAs force is acting only in the vertically upward direction ⇒θ=90o−30o=60o ⇒W=2×10×cos60=10kJ Hence correct answer is option C

How much is the work done in pulling up a block of wood weighing $2 K N$ for a length of $10 m$ on a smooth plane inclined at an angle of $30^{o}$ with the horizontal ? (in kJ)

The correct option is C $10$
Work done $W = F . s cos θ$
Here $θ =$ angle b/w force and displacement
As force is acting only in the vertically upward direction
$\Rightarrow θ = 90^{o} - 30^{o} = 60^{o}$
$\Rightarrow W = 2 \times 10 \times cos 60 = 10 k J$

Hence correct answer is option $C$