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Heat of Formation

How much latt...

Question

How much lattice enthalpy is released in formation of NaCl

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Solution

For NaCl, the lattice dissociation enthalpy is +787 kJ mol-1. You should talk about "lattice formation enthalpy" if you want to talk about the amount of energy released when a lattice is formed from its scattered gaseous ions. For NaCl, the lattice formation enthalpy is -787 kJ mol-1

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Q. "In ionic slids the sum of the electron gain enthalpy and ionization enthalpy may be positive but still the structure gets stabilised due to the energy released in the formation of the crystal lattice".explain.

Q. The lattice energy of

N a C l (s)

- 790 k J . {m o l}^{- 1}

and enthalpy of hydration is

- 785 k J . {m o l}^{- 1}

. Calculate the enthalpy of the solution of

N a C l (s)

.

Q. Assertion :Sodium chloride (

N a C l

) is a stable ionic solid. Reason:

N a C l

has high lattice enthalpy.

N a C l_{(s)} ⟶ N a^{+} (g) + C l^{-} (g)

The enthalpy of above reaction is known as:

Q. The change in enthalpy for hydration of ( i ) the chloride ion ; ( ii ) the iodide ion are :
Given :
* enthalpy change of solution of NaCl(s)

= - 2

kJ / mol.
* enthalpy change of solution of NaI(s)

= + 2

kJ / mol.
* enthalpy change of hydration of

N a^{+} (g) = - 390

kJ / mol.
* lattice enthalpy of NaCl

= - 772

kJ / mol.
* lattice enthalpy of NaI

= - 699

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