How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate if the law of conservation of mass is followed?

22.85 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

108 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

17.0 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

28.70 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 17.0 g
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants
For the chemical reaction: $A g N O_{3} + N a C I \to N a N O_{3} + A g C I$
$m_{r e a c t a n t s} = m_{p r o d u c t s}$
$m_{A g N O_{3}} + m_{N a C l} = m_{N a N O_{3}} + m_{A g C l}$
$x + 5.85 = 8.5 + 14.35$
$x = 17.0 g$
option C is correct

Suggest Corrections

Similar questions

N a C l

A g N O_{3}

A g C l

N a N O_{3}

N a C l

A g N O_{3}

A g C l

N a N O_{3}

N a C l

A g N O_{3}

A g C l

N a N O_{3}

Sodium chloride reacts with silver nitrate to produce silver chloride and sodium nitrate

(a) Write the equation.

(b) Check whether it is balanced, if not balance it.

(d) State the law that this equation satisfies.

Join BYJU'S Learning Program