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Question

How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?

A
11.79g
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B
15.38g
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C
10.81g
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D
25.35g
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Solution

The correct option is A 11.79g
Sodium acetate is C2H3O2Na
molar mass = 82 g/mol
Given: molarity, M=0.575 M, volume of solution, V=250 mL
number of moles, n=massmolar mass=m82
Using the relation: M=nV×1000
substitute the values:
0.575=m250×82×1000
m=11.79 g

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