How much momentum will a dumb-bell of mass $10$ kg transfer to the floor if it falls from a height of $80$ cm ? Take its downward acceleration to be $10$ m $s^{- 2}$

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Solution

Given,
Mass $= 10 k g$
Height, $S = 80 c m = 0.8 m$
$g = 10 m / s^{2}$

By third equation of motion, we can get velocity,
$v^{2} = u^{2} + 2 g S$

$\Rightarrow v^{2} = 2 \times 10 \times 0.8 = 16 = 4 m / s$
So, velocity $= 4 m / s$

Now Momentum , $= m a s s \times v e l o c i t y$
So, $\Rightarrow 10 \times 4 = 40 k g m / s$

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How much momentum will a dumb-bell of mass 10kg transfer to the floor if it falls from a height of 80cm ? Take its downward acceleration to be 10m s−2

Given, Mass=10kgHeight, S=80cm=0.8mg=10m/s2By third equation of motion, we can get velocity,v2=u2+2gS⇒v2=2×10×0.8=16=4m/sSo, velocity =4m/sNow Momentum ,=mass×velocitySo, ⇒10×4=40kgm/s

How much momentum will a dumb-bell of mass $10$ kg transfer to the floor if it falls from a height of $80$ cm ? Take its downward acceleration to be $10$ m $s^{- 2}$