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Question

# How much momentum will a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm (assume that the dumbbell stops after hitting the ground)? Take g = 10 ms−2

A

40 kg ms1

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B

50 kg ms1

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C

30 kg ms1

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D

35 kg ms1

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Solution

## The correct option is A 40 kg ms−1​ Mass of the dumbbell, m= 10 kg Distance covered by the dumbbell, s=80cm=0.8m Acceleration in the downward direction,a= 10 ms−2 Initial velocity of the dumbbell, u= 0 Final velocity of the dumbbell(when it was about to hit the floor) = v According to the third equation of motion v2−u2=2as⇒v=√u2+(2×a×s) ⇒v=√0+(2×10×0.8) = 4 ms−1​ Hence, the momentum(p) with which the dumbbell hits the floor is p=m×v=10×4=40 kg ms−1​ Therefore, dumbbell will exert a momentum of 40 kg ms−1​ to the floor

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