How much pressure will be felt by a gas ballon which at 100 m depth in a sea form sea level?

1081320

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98

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9.8 \times 10^{5}

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1.58 \times 10^{6}

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Solution

The correct option is A $1081320$ Pa
$P = P_{O} + ρ_{g} h$

$P_{O} =$ atmospheric pressure $= 1.013 \times 10^{5} P a$

$ρ =$ density of $H_{2} O = 1000 k g / m^{3}, g = g r a v i t y = 9.8 m / s^{2}$

$P =$ pressure experienced by gas balloon

$h =$ depth of the balloon from sea level= $100 m$

$P = (1.0132 \times 10^{5}) + (1000) (9.8) (100)$

$P = 1081320 P a$

So, the correct option is $A$

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How much pressure will be felt by a gas ballon which at 100 m depth in a sea form sea level?

The correct option is A 1081320 PaP=PO+ρghPO= atmospheric pressure=1.013×105Paρ= density of H2O=1000kg/m3,g=gravity=9.8m/s2P= pressure experienced by gas balloonh= depth of the balloon from sea level= 100mP=(1.0132×105)+(1000)(9.8)(100)P=1081320Pa So, the correct option is A