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Question

how much quantity of limestone will be required to prepare 1. 100 kg of cao and 200 kg limewater

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Solution

CaCO3 CaO +CO2100 g 56 g56 g of CaO is prepared from 100 g of CaCO3. So for 1.1 Kg (1.1 ×103 g) of CaO the amount of CaCO3 = 10056 × 1.1 × 103 =1.964 × 103 g or 1.964 Kg of lime stone2) CaO + H2O ----> Ca(OH)2 56 g 74 g74 g of Ca(OH)2 is prepared from 56 g of CaO.So 200 Kg lime water is prepared from = 5674 × 200 × 103 = 151.35 × 103 g = 151.35 Kg of CaO1.1 Kg of CaO is prepared from 1.964 Kg of CaCO3151.35 Kg of CaO is prepared from = 1.9641.1 × 151.35 = 270.23 Kg of lime stone

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