How much quantity of radioactive substance will remain in decayed after 5 half-lives period ?

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Solution

Initial quantity $\to A_{o}$
After $1^{s t}$ half life $\to A_{o} / 2$
After $2^{n d}$ half life $\to (A_{o} / 2) / 2 = A_{o} / 4$
After $3^{r d}$ half life $\to (A_{o} / 4) 2 = A_{o} / 8$
After $4^{t h}$ half life $\to (A_{o} / 8) / 2 = A_{o} / 16$
After $5^{t h}$ half life $\to (A_{o} / 16) / 2 = A_{o} / 32$ .

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Question 140(i)

Consider a quantity of a radioactive substance. The fraction of this quantity that remains after t half-lives can be found by using the expression $3^{- t}$
What frcation of the substance remains after 7 half-lives?

Question 140(i)

Question 140(ii)

Consider a quantity of a radioactive substance. The fraction of this quantity that remains after t half-lives can be found by using the expression $3^{- t}$ .
After how many half-lives will the fraction be $\frac{1}{243}$ of the original?

Question 140(ii)

Q. The percentage of quantity of a radioactive material that remains after

5

half-lives will be

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How much quantity of radioactive substance will remain in decayed after 5 half-lives period ?

Initial quantity →AoAfter 1st half life →Ao/2After 2nd half life →(Ao/2)/2=Ao/4After 3rd half life →(Ao/4)2=Ao/8After 4th half life →(Ao/8)/2=Ao/16After 5th half life →(Ao/16)/2=Ao/32.