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Question

# How much resistance is to be connected in series with the potentiometer wire to have a potential gradient of 0.05 mV cm−1?

A
1990Ω
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B
2000Ω
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C
1995Ω
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D
none of these
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Solution

## The correct option is B 1995ΩHere,k=0.05 mV cm−1=5 mV m−1Let R be the resistance is to be connected in series with the potentiometer wire, the potential of driver cell isV=I(R+5).................................................(1)The current through the potentiometer wire is,I=klr=5×10−3×15=10−3AHence, from(1)2=I(R+r)=10−3(R+5) R=2000−5R=1995Ω

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