How much silver will be obtained by that quantity of current which displaces $5.6 l i t r e$ of $H_{2}$ ?

54 g

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13.5 g

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20 g

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108 g

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Solution

The correct option is A $54 g$
$22.4 l$ volume occupied by $H_{2}$ = $1 m o l$
$5.6$ volume occupied by $H_{2}$ = $\frac{1}{22.4}$ $\times 5.6$
= $0.25 m o l$
= $0.25 m o l$ $\times$ $\frac{2 g . e q}{1 m o l}$
= $0.5 g . e q$
Wt. of silver obtained = $0.5 \times 108$
= $54 g$ .
Hence the correct option is 'A'.

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