how much stress is required to double the length of a wire of young's modulus Y

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Solution

Young's modulus
Y = (F/A)/(ΔL/L)
As the length of the wire is doubled, the change in length is equal to its original length. If Lis the original length,
then ΔL= L.
Therefore Y = F/A
Stress, F=Y *A

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how much stress is required to double the length of a wire of young's modulus Y

Young's modulus Y = (F/A)/(ΔL/L) As the length of the wire is doubled, the change in length is equal to its original length. If Lis the original length, then ΔL= L. Therefore Y = F/A Stress, F=Y *A

Young's modulus
Y = (F/A)/(ΔL/L)
As the length of the wire is doubled, the change in length is equal to its original length. If Lis the original length,
then ΔL= L.
Therefore Y = F/A
Stress, F=Y *A