Question

How much time is required for complete decomposition of $4$ moles of water using $4A$?

• A. $3.86\times {10}^{5}sec$
• B. $1.93\times {10}^{5}sec$
• C. $9650sec$
• D. $48250sec$

Answer 1

Answer: (B)

$1.93\times {10}^{5}sec$

Let $t$ sec be used ; No. of faradays $=\frac{4\times t}{96500}$
no. of moles of $H_{2}O=4$, no. of equivalents of $H_{2}O=4\times 2$
$\therefore$ $\frac{4\times t}{96500}=4\times 2$
$\Rightarrow$ $t=1.93\times {10}^5$ {Option B}