Question

How much time is required for the complete decomposition of two moles of water using a current of 4 A.

• A. $3.86\times {10}^{5}sec$
• B. $1.93\times {10}^{5}sec$
• C. $96500sec$
• D. $48250sec$

Answer 1

The correct option is C $96500sec$

We know that 4 moles of electrons are required for decompostion of two moles of $H_{2}O$.
Four moles of electrons contributes 4 Faradays of charge,
$NumberofFaradays=\frac{Q}{96500}$
$Q=I\times t$
If it takes t seconds to do this, then:
Number of Faradays $=\frac{4\times t}{96500}$
Time required for 2 moles of $H_{2}O$,
$4=\frac{4\times t}{96500}$
$t=96500sec$