Question

How much volume of air will be needed for complete combustion of $10L$ of ethane?

• A. $135L$
• B. $35L$
• C. $175L$
• D. $205L$

Answer 1

Answer: (B)

$35L$

$C_2{H}_6+\frac{7}{2}{O}_2⟶2C{O}_2+3H_{2}O$

At constant temperature nd pressure,

Volume $\alpha$ no. of moles.

$\therefore$ $\frac{V_{C_2{H}_6}}{V_{O_2}}=\frac{n_{C_2{H}_6}}{n_{O_2}}=\frac{2}{7}$ {as per stichiometry}

$\therefore$ $V_{O_2}=\frac{10\times 7}{2}=35L$

$\therefore$ Volume of air needed is $35L$.