How much water (in liters) has the camel to drink to keep its body temperature $34^{o} C$ by evaporation of sweat during the day $(12 h)$ instead of rising to $40^{o} C$ ?

41.4 L

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3.45 L

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414 L

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34.5 L

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Solution

The correct option is C $3.45 L$
Energy released due to change in temperature=energy required for phase change

$M_{c a n e l} C_{c a n e l} Δ T = m_{w a t e r} L$

or $m_{w a t e r} = \frac{400 \times 3480 \times 6}{2.42 \times 10^{6}} = 3.45 L$

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How much water (in liters) has the camel to drink to keep its body temperature 34oC by evaporation of sweat during the day (12 h) instead of rising to 40oC?

The correct option is C 3.45LEnergy released due to change in temperature=energy required for phase changeMcanelCcanelΔT=mwaterLor mwater=400×3480×62.42×106=3.45L

How much water (in liters) has the camel to drink to keep its body temperature $34^{o} C$ by evaporation of sweat during the day $(12 h)$ instead of rising to $40^{o} C$ ?

The correct option is C $3.45 L$
Energy released due to change in temperature=energy required for phase change

$M_{c a n e l} C_{c a n e l} Δ T = m_{w a t e r} L$

or $m_{w a t e r} = \frac{400 \times 3480 \times 6}{2.42 \times 10^{6}} = 3.45 L$