How much water should be mixed with 12 ml of alcohol so as to obtain 12% of alcohol solution?

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Solution

$V o l u m e p e r c e n t = \frac{V o l u m e o f s o l u t e (a l c o h o l)}{V o l u m e o f s o l u t i o n} 12 % = \frac{12}{V o l u m e o f w a t e r} \frac{12}{100} = \frac{12}{V o l u m e o f w a t e r} V o l u m e o f w a t e r = 100 m l$
100 ml of water should be mixed with 12 ml of alcohol so as to obtain 12% of alcohol solution.

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