Given P = ₹10,000
R = 10%
time (T) = 2 + 0.5 = 2.5
S.I = P×R×T100=10,000×10×2.5100=₹2500
Amount = P + S.I = ₹10,000 + ₹2500 = ₹12,500
What amount Rajiv will receive if he invests ₹ 10,000 at a rate of 10% per annum simple interest on April 18, 2020, if he invests the money on September 12, 2017
A man invested ₹ 1000 for 3 years at 11per cent simple interest per annum and ₹1000 at 10 % compounded interest per annum compounded annually for three years. Find which investment is better.