How much work is done when a force of $1 N$ moves a body through a distance of $1 m$ in its own direction?

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Solution

Given,
Force acting is $= F = 1 N$
The distance covered by body is $= d = 1 m$

Since the body moves in the direction of force, so angle between them is zero
$W = F \times d \times c o s (0)$
$W = 1 N \times 1 m \times 1$
$W = 1 J$

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How much work is done when a force of 1 N moves a body through a distance of 1 m in its own direction?

Given, Force acting is =F=1NThe distance covered by body is =d=1mSince the body moves in the direction of force, so angle between them is zeroW=F×d×cos(0)W=1N×1m×1W=1J

How much work is done when a force of $1 N$ moves a body through a distance of $1 m$ in its own direction?

Given,
Force acting is $= F = 1 N$
The distance covered by body is $= d = 1 m$

Since the body moves in the direction of force, so angle between them is zero
$W = F \times d \times c o s (0)$
$W = 1 N \times 1 m \times 1$
$W = 1 J$