How much work should be done on a car of mass 1000 kg to increase its speed from 10 m/s to 20 m/s (Ignore air resistance and friction).

200000 J

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250000 J

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150000 J

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50000 J

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Solution

The correct option is C 150000 J
We know that the work done is the change in kinetic energy.

Thus, $W = \frac{1}{2} m v_{f}^{2} - \frac{1}{2} m v_{i}^{2} = \frac{1}{2} \times 1000 [20^{2} - 10^{2}] = 15000 J$

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How much work should be done on a car of mass 1000 kg to increase its speed from 10 m/s to 20 m/s (Ignore air resistance and friction).

The correct option is C 150000 JWe know that the work done is the change in kinetic energy.Thus, W=12mv2f−12mv2i=12×1000[202−102]=15000J

The correct option is C 150000 J
We know that the work done is the change in kinetic energy.

Thus, $W = \frac{1}{2} m v_{f}^{2} - \frac{1}{2} m v_{i}^{2} = \frac{1}{2} \times 1000 [20^{2} - 10^{2}] = 15000 J$