How this equation will be balanced? Mg(co3)2 + Hcl -----> MgCl + H2o +CO2

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balance this equation

Cu(HCO₃)₂+ HCl => CuCl₂+ H₂O + CO₂

CO2+H20 gives C6H12O6+O2+H2O

How to balance this equation as per short cut method taught in byju's class session

Na2CO3+Hcl,_______≥NaCL+NaHCO3. Na2CO3+HcL________≥NaCL+H2o+CO2 why is it written like that ,is this equation both write?

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

C a C O_{3} + H C l \to C a C l_{2} + H_{2} O + C O_{2}

M n O_{2} + H C l \to M n C l_{2} + H_{2} O + C l_{2}

M g (O H)_{2} + H C l \to M g C l_{2} + H_{2} O

K I + H_{2} S O_{4} \to K H S O_{4} + I_{2} + S O_{2}

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