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Byju's Answer
Standard VIII
Mathematics
Transposing Method
how to take L...
Question
how to take LCM if no is x+1/x-1+x-2/x+2 =3
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Solution
Dear Student,
Consider
the
following
equation
.
x
+
1
x
-
1
+
x
-
2
x
+
2
=
3
The
denominator
of
the
two
fractions
on
the
LHS
are
x
-
1
and
x
-
2
.
Both
of
them
do
not
have
any
common
factor
.
So
their
LCM
can
be
determined
by
the
product
of
both
of
them
.
The
LCM
is
x
-
1
x
-
2
.
The
given
expression
can
be
simplified
as
follows
:
x
+
1
x
+
2
+
x
-
2
x
-
1
x
-
1
x
+
2
=
3
x
2
+
2
x
+
x
+
2
+
x
2
-
x
-
2
x
+
2
x
2
+
2
x
-
x
-
2
=
3
2
x
2
+
4
x
2
+
x
-
2
=
3
2
x
2
+
4
=
3
x
2
+
x
-
2
2
x
2
+
4
=
3
x
2
+
3
x
-
6
3
x
2
+
3
x
-
6
-
2
x
2
-
4
=
0
x
2
+
3
x
-
10
=
0
Solve
the
above
equation
as
,
x
2
+
5
x
-
2
x
-
10
=
0
⇒
x
x
+
5
-
2
x
+
5
=
0
⇒
x
+
5
x
-
2
=
0
⇒
x
=
-
5
,
2
Regards
Suggest Corrections
0
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