How will this justify the following order of acidic strength:
CH3CH2CHOOH>(CH3)2CHCOOH>(CH3)3COOH

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Solution

Electron donating group decreases the strength of acid, and electron withdrawing group increases the acidity. With increase in electron donating (+I) methyl group acidity gradually decreases.

Thus the acidity order is CH3CH2COOH> (CH3)2CHCOOH > (CH3)3CCOOH

So CH3CH2COOH is most acidic.

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C H_{3} C O O H

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What is the correct increasing order of extent of deprotonation for the following acids in their aqueous solutions?

(I) $(C H_{3})_{2} C H C O O H$

(II) $C H_{3} C H_{2} C O O H$

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