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Question

# The increasing order of acidic strength in the following acids. ClCH2COOH,CH3CH2COOH,ClCH2CH3COOH,(CH3)2CHCOOH and CH3COOH is:

A
(CH3)2CHCOOH<CH3CH2COOH<ClCH2CH2COOH<CH3COOH<ClCH2COOH
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B
CH3CH2COOH<(CH3)2CHCOOH<ClCH2CH2COOH<CH3COOH<ClCH2COOH
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C
(CH3)2CHCOOH<CH3CH2COOH<ClCH2CH2COOH<ClCH2COOH<CH3COOH
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D
(CH3)2CHCOOH<ClCH2CH2COOH<CH3CH2COOH<CH3COOH<ClCH2COOH
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Solution

## The correct option is C (CH3)2CHCOOH<CH3CH2COOH<ClCH2CH2COOH<CH3COOH<ClCH2COOHElectron donating group decreases the strength of the acid Electron withdrawing group increases the strength of the acid Since −CH3 is an electron-donating group, it decreases the acidity∴(CH3)2CHCOOH<CH3CH2COOH<CH3COOH−Cl is an electron withdrawing group, it increases the acidity ∴ClCH2CH2COOH<ClCH2COOHThe increasing order of acid strength is ∴(CH3)2CHCOOH<CH3CH2COOH<ClCH2CH2COOH<CH3COOH<ClCH2COOH

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