wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How will you connect three resistors of 2 Ω, 3 Ω and 5 Ω respectively so as to obtain a resultant of 2.5 Ω? Draw the diagram to show the arrangement.

Open in App
Solution

To get the resistance of 2.5 Ώ, we will have to connect the resistors of values 2 Ώ and 3 Ώ in series and this arrangement should be connected in parallel with the resistor of value 5 Ώ.


Resistance 2 Ω and 3 Ω are in series their net resistance is R=R1 +R2 R =2 Ω +3 Ω R=5 ΩThis 5 Ω resistance is in parallel with another 5 Ω resistance therefore their net resistance is:' 1R=1R1+1R2 1R=15+15 1R=25 R=2.5 Ω Hence, net resistance of the combination will be 2.5 Ω

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon