How will you obtain the following (Give only chemical equations)?
(i) $N_{2}$ from ${N H}_{3}$
(ii) ${N H}_{3}$ from ${N H}_{4} C l$

Open in App

Solution

(i) $N_{2}$ from ${N H}_{3}$ by oxidation:
$8 N H_{3} + 3 C l_{2} \to 6 N H_{4} C l + N_{2}$
$2 N H_{3} + 3 C u O heat - - \to 3 C u + N_{2} + 3 H_{2} O$
(ii) ${N H}_{3}$ from ${N H}_{4} C l$
$2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3} ↑$

Suggest Corrections

Similar questions

{N H}_{3} + {C l}_{2} \to N_{2} + {N H}_{4} C l

N H_{4} C l

N H_{3}

C l_{2}

N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

N H_{4} C l \to N H_{3} + H C l

(A), (B), (C)

(D)

(A) + N a O H H e a t ⟶ N a C l + N H_{3} + H_{2} O

N H_{3} + C O_{2} + H_{2} O ⟶ (B)

(B) + N a C l ⟶ (C) + N H_{4} C l

(C) H e a t ⟶ N a_{2} C O_{3} + H_{2} O + (D)

Join BYJU'S Learning Program