Question

Identify $\left(A\right),\left(B\right),\left(C\right)$ & $\left(D\right)$ and give their chemical formulae:
(i) $\left(A\right)+NaOH\stackrel{Heat}{⟶}NaCl+N{H}_3+H_{2}O$
(ii) $N{H}_3+C{O}_2+H_{2}O⟶\left(B\right)$
(iii) $\left(B\right)+NaCl⟶\left(C\right)+N{H}_{4}Cl$
(iv) $\left(C\right)\stackrel{Heat}{⟶}N{a}_{2}C{O}_3+H_{2}O+\left(D\right)$

• A. $\left(A\right)-N{H}_{4}Cl$ $\left(B\right)-N{H}_{4}HC{O}_3$ $\left(C\right)-NaHC{O}_3$ $\left(D\right)-C{O}_2$
• B. $\left(A\right)-N{H}_{3}C{l}_2$ $\left(B\right)-N{H}_{4}HC{O}_3$ $\left(C\right)-NaHC{O}_4$ $\left(D\right)-C{O}_2$
• C. $\left(A\right)-N{H}_{4}Cl$ $\left(B\right)-N{H}_{3}HC{O}_2$ $\left(C\right)-NaHC{O}_4$ $\left(D\right)-C{O}_2$
• D. None of these

Answer 1

The correct option is A $\left(A\right)-N{H}_{4}Cl$ $\left(B\right)-N{H}_{4}HC{O}_3$ $\left(C\right)-NaHC{O}_3$ $\left(D\right)-C{O}_2$

(i) This is an example of a double displacement reaction, where the cations and anions of the two reaction compounds are exchanged, forming two entirely different compounds.
(ii) In this reaction ammonium bicarbonate is produced by combining carbon dioxide and ammonia.
(iii) Ammonium bicarbonate reacts with alkali metal halides, giving alkali metal bicarbonate and ammonium halide.
(iv) Upon heating, sodium bicarbonate decomposes to produce sodium carbonate, carbon dioxide and water.