Hybridisation of iodine in $I F_{7}$ molecule is:

s p^{3}

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s p^{3} d

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s p^{3} d^{2}

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s p^{3} d^{3}

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Solution

The correct option is D $s p^{3} d^{3}$
Here, iodine forms $7$ bonds with $7$ fluorine atoms. Hence, $7$ orbitals are involved in hybridization which is $s p^{3} d^{3}$ .

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