$M o l e c u l e H y b r i d i s a t i o n S h a p e$

$A . P O_{4}^{- 3} 1. s p^{2} a) D i s t o r t e d o c t a h e d r a l$

$B . X e F_{6} 2. s p^{3} b) P y r a m i d$

$C . S O_{3}^{- 2} 3. s p^{3} d c) T e t r a h e d r a l$

$D . N O_{3}^{- 1} 4. s p^{3} d^{3} d) T r i a n g u l a r p l a n a r$

The correct match is

D - 1 - d

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C - 1 - d

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A - 2 - b

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B - 4 - c

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Solution

The correct option is A D - 1 - d
$H y b r i d i s a t i o n o f N i n N O_{3}^{- 1} = 5 - \frac{(- 1)}{2} = \frac{6}{2} = 3 h y b r i d o r b i t a l s$

Suggest Corrections

Similar questions

C (1) H_{2} = C (2) H - C (3) \equiv C H

The correct order of hybridisation of the central atom in the following species $N H_{3}$ , ${[P t C l_{4}]}^{2 -}$ , $P C l_{5}$ and $B C l_{3}$

C (1) H_{2} = C (2) H - C (3) \equiv C H

A l H_{3}

A l H_{4}^{-}

s p^{3}, s p^{2}, s p^{2}, s p^{3}

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