Question

Hybridised state of Fe in $\left[Fe\right(H_{2}O{)}_{5}NO]S{O}_4$ is:

• A. $s{p}^{3}d$
• B. $s{p}^3{d}^2$
• C. $s{p}^3{d}^3$
• D. $ds{p}^2$

Answer 1

The correct option is B $s{p}^3{d}^2$

oxidation state of Fe = +1
Electron configuration of $F{e}^{+}$
$=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}3d^6$
Final configuration
$=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{7}4s^{\circ }4p^{\circ }4d^{\circ }$
Hybridisation $=S{p}^3{d}^2$.