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B
sp3d2
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C
sp3d3
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D
dsp2
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Solution
The correct option is Bsp3d2 oxidation state of Fe = +1 Electron configuration of Fe+ =1s22s22p63s23p64s13d6 Final configuration =1s22s22p63s23p63d74s∘4p∘4d∘ Hybridisation =Sp3d2.