Question

Hybridization and magnetic behaviour of complex $K_4\left[Mn\right(CN{)}_6]$ is:

• A. $d^{2}s{p}^3$, diamagnetic
• B. $d^{2}s{p}^3$, paramagnetic
• C. $s{p}^3{d}^2$, diamagnetic
• D. $s{p}^3{d}^2$, paramagnetic

Answer 1

Answer: (B)

$d^{2}s{p}^3$, paramagnetic

$K_4\left[Mn\right(CN{)}_6]$ has $Mn$ in $+2$ state with a strong field ligand $C{N}^{-}$. It will pair the electrons and leave two empty 3d orbitals. Hence, the hybridization is $d^{2}s{p}^3$. Since, there is one unpaired electron, it is paramagnetic.