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Question

Hybridization and structure of $$XeF_4$$ is:


A
sp3d, triogonal bipyramidal
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B
sp3, tetrahedral
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C
sp3d2, square planar
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D
sp3d2, hexagonal
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Solution

The correct option is B $$sp^3d^2$$, square planar
In $$XeF_{4}$$ out of 8 valencies of Xe 4 are satisfied by F. Thus, it Xe has 4 bond pair and 2 lone pairs. Thus its hybridization is $$sp^{3}d^{2}$$ and its geometry is square planar.

Chemistry

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