Hydration of ethyne to ethanal takes place through the formation of :

C H_{3} C H (O H)_{2}

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C H_{2} = C H O H

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C H_{2} = C H O^{-}

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C H \equiv C^{-}

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Solution

The correct option is C $C H_{2} = C H O H$
$H C \equiv C H + H_{2} O H_{2} S O_{4} / (d i l) - ------ \to H g S O_{4} H_{2} C = C H O H e t h e n o l (u n s t a b l e)$
$r e a r r a n g e m e t ⇌ t a u t o m e r i s m H_{3} C - O | | C - H e t h a n o l$

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C H_{3} C H_{3} > C H_{2} = C H_{2} > H C = C h

H O C l (C l_{2} + H_{2} O)

The IUPAC name of

$C H_{3} - C H | C H_{3} - C | C H_{3} - C H | C H O - C H_{2} - C H_{2} - C H_{3}$ is?

C H_{3} - C H O

C H_{2} = C H O H

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