Hydrazine reacts with KIO3 In the presence of HCl as- N2H4 - IO3- - 2H- - Cl- ICI - N2 - 3H2OThe equivalent masses of N2H4 and KIO3 respectively are- - KIO3 - 214-

The correct option is A 16 and 53.5 2N_2H_4++5IO_3^ +2H^++Cl^ ⟶+1ICl+0N_2+3H_2O Equivalent weight of N_2H_4=M_N_2H_42[ 2 to 0] #160; ...

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Byju's Answer

Standard XII

Chemistry

Van't Hoff Factor

Hydrazine rea...

Question

Hydrazine reacts with $K I O_{3}$ In the presence of $H C l$ as:
$N_{2} H_{4} + I O_{3}^{-} + 2 H^{+} + C l^{-} \to I C I + N_{2} + 3 H_{2} O$
The equivalent masses of $N_{2} H_{4}$ and $K I O_{3}$ respectively are:
[ $K I O_{3} = 214$ ]

8

and

53.5

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16

and

53.5

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8

and

35.6

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8

and

87

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Solution

The correct option is A $16$ and $53.5$
$_{2} H_{4} +^{-} + 2 H^{+} + C l^{-} ⟶ + 1 I C l +_{2} + 3 H_{2} O$
Equivalent weight of $N_{2} H_{4} = \frac{M_{N_{2} H_{4}}}{2} [- 2 to 0]$
$= \frac{32}{2} = 16$
Equivalent weight of $K I O_{3} = \frac{M_{K I O_{3}}}{4} [+ 5 to + 1]$
$= \frac{214}{4} = 53.5$

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Similar questions

Q. Hydro-zine reacts with

K I O_{3}

in presence of

H C l

N_{2} H_{4} + I O_{3}^{-} + 2 H^{+} + C l^{-} \to I C l + N_{2} + 3 H_{2} O

The equivalent masses of

N_{2} H_{4}

and

K I O_{3}

N_{2} H_{4}

reduces

I O_{3}^{-}

I^{+}

in acidic medium as :

N_{2} H_{4} + I O_{3}^{-} + H^{+} ⟶ N_{2} + I^{+} + H_{2} O

Equivalent mass of

K I O_{3}

(molar mass = 214 g mol

^{- 1}

) is :

Q. A

50 m L

1.92 %

w / v

solution of a metal ion

M^{n +} a t . w t = 60

was treated with

5.32 g

hydrazinehydrate

(N_{2} H_{4} . H_{2} O) 90 % p u r e

and the mixture was saturated with

C O_{2}

gas when entire metal gets pecipitated as a complex

[M (N H_{2} - N H C O O)_{n}]

the complex was filtered of and the filterate was titrated with

M / 10 K I O_{3}

in the presence of

c o n c . H C l

according to the following equation :

N_{2} H_{4} + I O_{3}^{-} + 2 H^{+} + C l^{-} \to I C l + 3 H_{2} O + N_{2} ↑

The volume of

M / 10 K I O_{3}

solution needed for end point to arrive was

480 m L

. Find the value of

n

Q. The equivalent mass of

K I O_{3}

I O_{3}^{-} ⟶ I C l

\frac{214}{x}

. The value of

x

is :

0.1 M

solution of

K I

reacts with excess of

H_{2} S O_{4}

and

K I O_{3}

solutions according to equation:

5 I^{-} + I O_{3}^{-} + 6 H \to 3 I_{2} + 3 H_{2} O

Which of the following statement is correct?

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Hydrazine reacts with KIO3 In the presence of HCl as: N2H4+IO−3+2H++Cl−→ICI+N2+3H2OThe equivalent masses of N2H4 and KIO3 respectively are: [KIO3=214]

The correct option is A 16 and 53.5−2N2H4++5IO3−+2H++Cl−⟶+1ICl+0N2+3H2OEquivalent weight of N2H4=MN2H42[−2 to 0] =322=16Equivalent weight of KIO3=MKIO34[+5 to +1] =2144=53.5

Hydrazine reacts with $K I O_{3}$ In the presence of $H C l$ as:
$N_{2} H_{4} + I O_{3}^{-} + 2 H^{+} + C l^{-} \to I C I + N_{2} + 3 H_{2} O$
The equivalent masses of $N_{2} H_{4}$ and $K I O_{3}$ respectively are:
[ $K I O_{3} = 214$ ]