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Reactions Due to Catalyst

Hydrogen and ...

Question

Hydrogen and carbon dioxide are gases. If they are formed in a reaction you will see bubble. This can be a sign that a chemical reaction has happened.

Write a balance chemical reaction for reaction between hydrogen and carbon dioxide gas.

A

C O_{2} (g) + H_{2} (g) \to C O (g) + H_{2} O (g)

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B

7 C O_{2} (g) + H_{2} (g) \to C O (g) + H_{2} O (g)

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C

C O_{2} (g) + 3 H_{2} (g) \to C O (g) + H_{2} O (g)

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D

C O_{2} (g) + 2 H_{2} (g) \to C O (g) + H_{2} O (g)

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Solution

The correct option is A $C O_{2} (g) + H_{2} (g) \to C O (g) + H_{2} O (g)$
When hydrogen reacts with carbon dioxide gas, it forms carbon monoxide and water.

$C O_{2} (g) + H_{2} (g) + 41.2 k J \to C O (g) + H_{2} O (g)$

Hence, option A is correct.

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Similar questions

Δ H_{f}^{o}

C O_{2 (g)}, C O_{(g)}

H_{2} O_{(g)}

- 393.5, - 110.5

- 241.8

k J . m o l^{- 1}

, respectively. The

Δ H_{f}^{o}

k J . m o l^{- 1}

] for the reaction,

C O_{2 (g)} + H_{2 (g)} \to C O_{(g)} + H_{2} O_{(g)}

Δ H_{t}^{\circ}

C O_{2 (g)}, C O_{(g)}

H_{2} O_{(g)}

- 393.5, - 110.5

- 241.8 k J m o l^{- 1}

respectively the standard enthalpy change (in

K J

) for the reaction

C O_{2 (g)} + H_{2 (g)} \to C O_{(g)} + H_{2} O_{(g)}

Δ H_{f}^{o}

C O_{2 (g)}

C O_{(g)}

H_{2} O_{(g)}

- 393.5

- 110.5

- 241.8

m o l^{- 1}

respectively the standard enthalpy change (in KJ) for the reaction

C O_{2 (g)} + H_{2 (g)} \to C O_{(g)} + H_{2} O_{(g)}

CoO (s) + H_{2} (g) ⇌ C o (s) + H_{2} O (g), K_{1} = 60

C o O (s) + C O (g) ⇌ C o (s) + C O_{2}, K_{2}

= 180 then the equilibrium constant of the reaction

C O_{2} (g) + H_{2} (g) ⇌ C O (g) + H_{2} O (g)

Δ H

k J

for the following reaction:

C (g) + O_{2} (g) \to C O_{2} (g)

H_{2} O (g) + C (g) \to C O (g) + H_{2} (g)

Δ H = + 131 k J

C O (g) + \frac{1}{2} O_{2} (g) \to {C O}_{2} (g)

Δ H = - 282 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (g)

Δ H = - 242 k J

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