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Question

If CoO(s)+H2(g)Co(s)+H2O(g),K1=60 ; CoO(s)+CO(g)Co(s)+CO2,K2 = 180 then the equilibrium constant of the reaction CO2(g)+H2(g)CO(g)+H2O(g) will be-

A
0.44
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B
0.11
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C
0.22
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D
0.33
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Solution

The correct option is D 0.33
the result reaction are coming then reaction 1 and opposite of reaction 2 added
K3=K1×1/K2
60×1/180
0.33 ans
D is correct

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