Question

Hydrogen and Helium volume V at same temperature T and same pressure P are mixed to have same volume.The resulting pressure of the mixture will be:

Answer 1

$$\begin{gathered} \mathrm{From}\mathrm{gas}\mathrm{equation}, \\ \frac{\mathrm{P}\text{'}\mathrm{V}}{\mathrm{T}}=\frac{{\mathrm{P}}_1{\mathrm{V}}_1}{{\mathrm{T}}_1}+\frac{{\mathrm{P}}_2{\mathrm{V}}_2}{{\mathrm{T}}_2} \\ \mathrm{Substitute}\mathrm{the}\mathrm{given}\mathrm{values}: \\ \frac{\mathrm{P}\text{'}\mathrm{V}}{\mathrm{T}}=\frac{\mathrm{PV}}{\mathrm{T}}+\frac{\mathrm{PV}}{\mathrm{T}}(\mathrm{assume}\mathrm{constant}\mathrm{temperature}\mathrm{of}\mathrm{the}\mathrm{mixing}) \\ \mathrm{Hence},\mathrm{the}\mathrm{pressure}\mathrm{of}\mathrm{the}\mathrm{mixture}\mathrm{is}, \\ \mathrm{P}\text{'}=\mathbf{2}\mathbf{P} \end{gathered}$$