Question

Two gases $A$ and $B$ having the same temperature $T$, same pressure $P$ and same volume $V$ are mixed. If the mixture is at the same volume $V$, the pressure of the mixture is

• A. $P$
• B. $P/2$
• C. $2P$
• D. $4P$

Answer 1

The correct option is C $2P$

From Ideal Gas Law,

$PV=nRT$

$⟹$ Moles of a gas=$n=\frac{PV}{RT}$

When the mixture is created, the total number of moles is equal to the sum of that of individual gases.

Hence $N=n_1+n_2$

$⟹\frac{P^{\prime }V}{RT}=\frac{PV}{RT}+\frac{PV}{RT}$

$⟹P^{\prime }=2P$