Two gases A&B having same pressure P, volume V and absolute temperature T are mixed. If the mixture has volume and temperature as V & T respectively then the pressure of mixture is

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Solution

The correct option is A 2P
Moles of gas A $= \frac{P V}{R T}$

Moles of gas B $= \frac{P V}{R T}$
Moles of the gas mixture $= \frac{P^{'} V}{R T}$
Since the number of moles(mass) remains same before and after mixing,
$\frac{P V}{R T} + \frac{P V}{R T} = \frac{P^{'} V}{R T}$
$⟹ P^{'} = 2 P$

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Two gases A&B having same pressure P, volume V and absolute temperature T are mixed. If the mixture has volume and temperature as V & T respectively then the pressure of mixture is

The correct option is A 2PMoles of gas A =PVRTMoles of gas B =PVRTMoles of the gas mixture =P′VRTSince the number of moles(mass) remains same before and after mixing,PVRT+PVRT=P′VRT⟹P′=2P

The correct option is A 2P
Moles of gas A $= \frac{P V}{R T}$

Moles of gas B $= \frac{P V}{R T}$
Moles of the gas mixture $= \frac{P^{'} V}{R T}$
Since the number of moles(mass) remains same before and after mixing,
$\frac{P V}{R T} + \frac{P V}{R T} = \frac{P^{'} V}{R T}$
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