Hydrogen bonding does not play any role in the boiling point of:

N H_{3}

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H_{2} O

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H I

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H F

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Solution

The correct option is C $H I$
Hydrogen bonding does not play any role in the bonding point of $H I$ .Because of the extensive network of hydrogen bonds between molecules, $H F$ has a higher boiling point than similar molecules $(H C l, H B r, H I)$ containing elements of the same group of the Periodic Table, but heavier and less electronegative. For such reason, $H F$ is liquid, whereas $H C l, H B r$ and $H I$ are gaseous at temperatures close to room temperature. Hydrogen bonding does not play any role in the bonding point of $H I$
Hence option C is correct.

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Similar questions

Question 04

Hydrogen bonds are formed in many compounds e.g., $H_{2} O, H F, N H_{3}$ . The boiling point of such compounds depends to a extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points above compounds is

(a) $H F > H_{2} O > N H_{3}$

(b) $H_{2} O > H F > N H_{3}$

(d) $N H_{3} > H_{2} O > H F$

The order of boiling point of $N H_{3}, H_{2} O, H F a n d P H_{3}$ is

Q. Among

N H_{3}, H_{2} O, H F

and

H_{2} S

which have the highest magnitude of hydrogen bonding?

Q. Explain the hydrogen bonding in molecules of

H F,

H_{2} O

and

N H_{3}

$A s s e r t i o n - --------- -$ (A): The boiling point of HF is higher than that of $H_{2} O$
$R e a s o n - ------- -$ (R): The hydrogen bond strength in HF is lower than that in $H_{2} O$

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