Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen- according to the equation- 2H2O2aq - 2H2Ol - O2g under conditions- where 1 mole of gas occupies 24 dm3 - 100 dm3 of X M solution of H2O2 produces 3 dm3 of O2- Thus- X is-

The correct option is A 2.5 3 dm^3×1 mole24 dm^3=0.125 moles of O_2 2H_2O_2 ⟶ 2H_2O + O_2 2 moles of H_2O_2 produces 1 mole of O_2 . 0. ...

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Standard XII

Chemistry

Potassium Permanganate

Hydrogen pero...

Question

Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen, according to the equation:
$2 H_{2} O_{2} (a q) \to 2 H_{2} O (l) + O_{2} (g)$
under conditions, where 1 mole of gas occupies $24 d m^{3} . 100 d m^{3}$ of X M solution of $H_{2} O_{2}$ produces $3 d m^{3}$ of $O_{2}$ .

Thus, X is:

2.5

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0.5

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0.25

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Solution

The correct option is A 2.5
$3 d m^{3} \times \frac{1 m o l e}{24 d m^{3}} = 0.125 m o l e s o f O_{2}$

$2 H_{2} O_{2} ⟶ 2 H_{2} O + O_{2}$

2 moles of $H_{2} O_{2}$ produces 1 mole of $O_{2}$ .

$0.125$ moles of $O_{2}$ requires $2 \times 0.125$ $H_{2} O_{2} = 0.25$ moles of $H_{2} O_{2}$

Concentration of $H_{2} O_{2} = \frac{0.25}{0.1} = 2.5 M$

Hence, option A is correct.

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Similar questions

2 H_{2} O_{2} (a q) ⟶ 2 H_{2} O (l) + O_{2} (g)

Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the given equation under conditions where one mole of gas occupies

24 d m^{3}

100 c m^{3}

x M

solution of

H_{2} O_{2}

produces

3 d m^{3}

O_{2}

Thus,

x

is :

Q. Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation:

2 H_{2} O_{2} (a q) ⟶ 2 H_{2} O (ℓ) + O_{2} (g)

Under conditions, where

1

mole of gas occupies

24 d m^{3}

100 c m^{3}

x M

solution of

H_{2} O_{2}

produces

3 d m^{3}

O_{2}

. Thus,

x

is:

Q. Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation:

2 H_{2} O_{2} (a q) \to 2 H_{2} O (l) + O_{2} (g)

under conditions where

1

mole of gas occupies

24 d m^{3} . 100 c m^{3}

X M

solution of

H_{2} O_{2}

produces

3 d m^{3}

O_{2}

Thus,

X

is:

2 H_{2} O_{2} (l) \to 2 H_{2} O (l) + O_{2} (g)

100

mL of

X

molar

H_{2} O_{2}

gives

3

L of

O_{2}

gas under the condition when

1

mol occupies

24

L. The value of

X

is :

Q. The mole fraction of hydrogen peroxide in 30% (weight / weight) aqueous solution of

H_{2} O_{2}

is _________________.

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Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen, according to the equation:2H2O2(aq)→2H2O(l)+O2(g) under conditions, where 1 mole of gas occupies 24dm3.100dm3 of X M solution of H2O2 produces 3dm3 of O2. Thus, X is:

The correct option is A 2.53dm3×1 mole24 dm3=0.125 moles of O22H2O2⟶2H2O+O22 moles of H2O2 produces 1 mole of O2.0.125 moles of O2 requires 2×0.125 H2O2=0.25 moles of H2O2Concentration of H2O2=0.250.1=2.5 MHence, option A is correct.