Hydrogen peroxide oxidises [Fe(CN)6]4− to [Fe(CN)6]3− in acidic medium but reduces [Fe(CN)6]3− to [Fe(CN)6)]4− in alkaline medium. The other products formed, repectively are:
A
H2O and (H2O+OH−)
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B
(H2O+O2) and H2O
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C
(H2O+O2) and (H2O+OH−)
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D
H2O and (H2O+O2)
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Solution
The correct option is DH2O and (H2O+O2) In acidic medium, [Fe(CN)6]4−+H2−1O2+2H+→[Fe(CN)6]3−+2H2−2O Here Fe is getting oxidised from (+2 to +3) and O of H2O2 is getting reduced from (-1 to -2).
In alkaline medium, [Fe(CN)6]3−+H2−1O2+2OH−→[Fe(CN)6]4−+0O2+2H2O Here Fe is getting reduced from (+3 to +2) and O of H2O2 is getting oxidised from (-1 to 0).