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Question

Hydrogen peroxide oxidises [Fe(CN)6]4 to [Fe(CN)6]3 in acidic medium but reduces [Fe(CN)6]3 to [Fe(CN)6)]4 in alkaline medium. The other products formed, repectively are:

A
H2O and (H2O+OH)
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B
(H2O+O2) and H2O
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C
(H2O+O2) and (H2O+OH)
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D
H2O and (H2O+O2)
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Solution

The correct option is D H2O and (H2O+O2)
In acidic medium,
[Fe(CN)6]4+H21O2+2H+[Fe(CN)6]3+2H22O
Here Fe is getting oxidised from (+2 to +3) and O of H2O2 is getting reduced from (-1 to -2).

In alkaline medium,
[Fe(CN)6]3+H21O2+2OH[Fe(CN)6]4+0O2+2H2O
Here Fe is getting reduced from (+3 to +2) and O of H2O2 is getting oxidised from (-1 to 0).

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