Hydrogen peroxide oxidises $[F e (C N)_{6}]^{4 -}$ to $[F e (C N)_{6}]^{3 -}$ in acidic medium but reduce $[F e (C N)_{6}]^{3 -}$ to $[F e (C N)_{6}]^{4 -}$ in alkaline medium. The other products formed are, respectively:

H_{2} O

and

(H_{2} O + O_{2})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} O

and

(H_{2} O + O H^{-})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(H_{2} O + O_{2})

and

H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(H_{2} O + O_{2})

and

(H_{2} O + O H^{-})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $H_{2} O$ and $(H_{2} O + O_{2})$
(i) $[F e^{+ 2} (C N)_{6}]^{4 -} + H_{2} O_{2} + 2 H^{+} \to [F e^{+ 3} (C N)_{6}]^{3 -} + 2 H_{2} O$

(ii) $[F e^{+ 3} (C N)_{6}]^{3 -} + H_{2} O_{2} + 2 O H^{-} \to [F e^{+ 2} (C N)_{6}]^{4 -} + O_{2} + 2 H_{2} O$
From the following reaction it is clear that option A is correct.

Suggest Corrections

Similar questions

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6})]^{4 -}

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6})]^{4 -}

F e (C N)_{6}^{x -} + H_{2} O_{2} + H^{+} \to F e (C N)_{6}^{y -} + H_{2} O

[F e (C N_{6})]^{p -} + H_{2} O_{2} + O H^{-} \to [F e (C N_{6})]^{q -} + O_{2} + H_{2} O

[F e (C N)_{6}]^{3 -} + N_{2} H_{4} + O H^{-} \to [F e (C N)_{6}]^{4 -} + N_{2} + H_{2} O

(i) H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2} (i i) H_{2} O_{2} + A g_{2} O \to 2 A g + H_{2} O + O_{2}

Join BYJU'S Learning Program