Hydrolysis of carbides of Be and Al produces methane.What is the ratio of number of moles of ${B e}_{2}$ C and ${A l}_{4}$ $C_{3}$ required to prepare 1 mole of methane?

3: 1

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4: 0.2

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1: 0.33

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1: 3

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Solution

The correct option is C
1: 0.33

${B e}_{2}$ C + 4 $H_{2}$ O $\to$ C $H_{4}$ ; ${A l}_{4}$ $C_{3}$ + 12 $H_{2}$ O $\to$ 3C $H_{4}$

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Similar questions

1 m o l e

A l^{3 +}

A l

1 m o l e

M n O_{4}^{-}

M n^{2 +}

How much charge is required for the following reductions :

(i) 1 mole of $A l^{3 +}$ to Al ?

(ii) 1 mole of $C u^{2 +}$ to Cu ?

(iii) 1 mole of $M n O_{4}^{-} t o M n^{2 +}$ ?

Which of the following on hydrolysis can give methane

A) $A l_{4} C_{3}$ B) $B e_{2} C$ C) Ca $C_{2}$ D) $C H_{3} M g C l$

A g N O_{3}, C u S O_{4}

A l C l_{3}

S i C, C a C_{2}, B e_{2} C, A l_{2} C_{6}, A l_{4} C_{3}, B_{4} C

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